Question

(13. A force of 10N is resolved into the perpendicular components. If the first component makes 30° with the force the magnitudes of the components are 1) 5N, 5N 2) 52N, 5 N 3) 53 N, 5N 4) 10 N, 1013 N​

Answer 1

option 3rd is correct answer.

Fcos30∘=Fx⇒Fx=5√3

Fy=Fcos60=5N

Given that the magnitude of force, F=10N

We know the rectangular components of a A are given by:

Acosθ and Asinθ

Therefore, magnitude of the  components of F will be 10cos30o and 10sin30o     

where, θ=30o as given

By putting the value of cos30o and sin30o the components are 53N and 5N.

Answer 2

Answer:

Fcos30°=Fx → Fx=5√3

Fy=Fcos60=5N

Given that the magnitude of force, F=10N

We know the rectangular components of a A are given by:

Acose and Asine

Therefore, magnitude of

the components of F will

be 10cos300 and 10sin300

where, 0-300 as given

By putting the value of cos300 and sin300 the components are 53N and 5N.