Question

13. A fruitseller buys some oranges at the rate of 4 for a rupee and an equal number at 5 for a rupee He sells the whole lot at 9 for two rupees Find his gain or loss per cent.

Answer 1

Dear Student,

⇒Answer :

∴Let no of oranges be x  

4 oranges= 1 rupee

1 orange=  $\frac{1}{4}$ rupee

x oranges= $\frac{x}{4}$ rupee

∵Similarly,

∴Another x oranges= $\frac{x}{5}$ rupee

Total cp of 2x oranges=  $\frac{x}{4} + \frac{x}{5}$= $\frac{9x}{20}$

Now,

∴For SP:

9 oranges=2 rupees

1 orange= $\frac{2}{9}$ rupees

∴2x oranges= $\frac{2}{9}$ × 2x =  $\frac{4x}{9}$ rupees  

∴Loss=  $\frac{9x}{20} - \frac{4x}{9} = \frac{x}{180}$  

loss%= $\frac{X}{180}$ × $\frac{20}{9X}$ × 100% = 1.12% loss