13. A gas in a cylinder is at pressure P. If
the masses of all the molecules are made
one third of their original value and
their speeds are doubled, then find the
resultant pressure.
[Ans: 4/3 P]
73
Answers
Answered by
0
here's your answer
m
2
=m
1/3
,v
rms2
=2v
rms1
as the speeds of all molecules are doubled
PressureP=
3
1
.
V
mN
.v
2
RMS
∴P
1
=
3
1
.
V
mN
.v
2
RMS1
∴P
2
=
3
1
.
V
mN
.v
2
RMS2
∴
P
1
P
2
=(
m
1
m
2
).
v
2
RMS1
v
2
RMS2
.
=(
m
1
m
1
/3
)(2)
2
=
3
4
∴P
2
=
3
4
P
1
=
3
4
P
This is the resultant pressure.
Answered by
0
Answer:
This your answer.
Explanation:
ANSWER
m2=m1/3,vrms2=2vrms1 as the speeds of all molecules are doubled
PressureP=31.VmN.v2RMS
∴P1=31.VmN.v2RMS1
∴P2=31.VmN.v2RMS2
∴P1P2=(m1m2).v2RMS1v2RMS2.
=(m
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