Question

13. A man is four times as old as his son. After 20 years, he will be twice as old as his
son at that time. Find their present ages
5s subtracted from here​

Answer 1

Answer:

Man= 40 and Son = 10

Step-by-step explanation:

Hope this will be helpful

Answer 2

Answer:

Son age =10

Fathers age=40

Explanation:

Consider the present age of son = x years

So the present age of father =4x years

After 20 years

Age of son =(x+20)years

Age of father =(4x+20)years

4x+20=2(x+20)

By further calculation

4x+20=2x+40

2x=20

x=20/2=10

x=10

So the present age of son =10 years

Present age of father =4×10=40 years.

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