Question

13. A match box measures 4cmx2.5cmx1.5cm.What will be the volume of a packet

containing 12 such match boxes? How many such packets can be placed in a card board

box whose size is 60cmx30cmx24cm​

Answer 1

$Let a = 0.\bar{6}6ˉ</p><p></p><p>As there is one number under bar, multiply by 10 on both sides of the equation given above.</p><p></p><p>∴ 10 x a = 10 x 0.\bar{6}6ˉ</p><p>⇒ 10a = 6.\bar{6}6ˉ</p><p></p><p>Now, subtract a(0.\bold{bar{0}}bar0 ) from both sides,</p><p></p><p>10a = 6.\bar{6}6ˉ</p><p>- a =  - 0.\bar{6}6ˉ</p><p>____________________</p><p>9a = 6    [bar cancel]</p><p>__________________</p><p></p><p>a = \dfrac{6}{9}96</p><p></p><p>a = \dfrac{2}{3}32</p><p></p><p></p><p>From above, a = 0.\bar{6}6ˉ</p><p>\therefore 0.\bar{6} = \dfrac{2}{3}∴0.6ˉ=32</p><p></p><p>Hence, 0.\bar{6}6ˉ inm p/q form is 2 / 3 .</p><p>$

Answer 2

Answer:

Step-by-step explanation:

volume of a packet=4cmx2.5cmx1.5cm =15

volume of a packet  containing 12 such match boxes=15x12 =180

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