13. A pair of dice is rolled. Find the probability of getting
() doublets
(i) sum is 6
(iii) sum is at least 10
(iv) sum is at most 5
(v) sum is multiple of 5.
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Answers
Answer:
i)Probability of getting doublets = 6/36 = 1/6
ii) Probability of getting the sum 6 = 5/36
iii) Probability of getting at least 10 = 11/36
iv) Probability of getting the sum is almost 5 = 4/36 = 1/9
v) Probability of getting the sum multiple of 5 = 9
Step-by-step explanation:
13.i) doublets means getting same digit in both the dices.
1 = 1
2 = 2
3 = 3
4 = 4
5 = 5
6 = 6
Probability of getting doublets = 6/36 = 1/6
ii) 2 + 4 = 6
4 + 2 = 6
5 + 1 = 6
1 + 5 = 6
3 + 3 = 6
Probability of getting the sum 6 = 5/36
iii) 9 + 1 = 10
9 + 2 = 11
9 + 3 = 12
5 + 5 = 10
5 + 6 = 11
6 + 6 = 12
8 + 2 = 10
8 + 3 = 11
8 + 4 = 12
6 + 4 = 10
6 + 5 = 11
Probability of getting at least 10 = 11/36
iv) 2 + 3 = 5
3 + 2 = 5
4 + 1 = 5
1 + 4 = 5
Probability of getting the sum is almost 5 = 4/36 = 1/9
v) 3 + 2 = 5
2 + 3 = 5
4 + 1 = 5
1 + 4 = 5
8 + 2 = 10
2 + 8 = 10
6 + 4 = 10
4 + 6 = 10
5 + 5 = 10
Probability of getting the sum multiple of 5 = 9