13. A particle moving with an initial velocity of 5m/s is subjected to a uniform acceleration of - 2.5m/s2. Find the displacement in the next 4 sec
Answers
Answered by
1
Displacement will be
S = 5(4)-2.5/2(4*4)
S= 20-2.5(8)
S= 20-20
The displacement will be null vector (0)
S = 5(4)-2.5/2(4*4)
S= 20-2.5(8)
S= 20-20
The displacement will be null vector (0)
Answered by
2
s=ut*1/2at2
=5*4+1/2*-2.5*16
=20-2.5*8
=20-20
=0
s(distance)=0m
therefore no distance is covered
hope you find it useful!!
=5*4+1/2*-2.5*16
=20-2.5*8
=20-20
=0
s(distance)=0m
therefore no distance is covered
hope you find it useful!!
madhav8:
Sir I need to find displacement according to questions
Similar questions