Question

13. A pea plant with yellow seeds (Y) & purple flowers (R) is crossed with plant having green seeds (y) & white flowers (r) obtain the genotypic ration in F2 generation. full explanation ​

Answer 1

Answer:

a pea plant with yellow round seeds is crossed with another plant with seeds.the genotype of yellow round seeds is YYRR and the genotype of green wrinkled seeds is yyrr.in the f1 generation, the progenies obtained are heterozygous yellow round since yellow and round are dominant characters

Answer 2

Answer:

Explanation:       RY            Ry           rY             ry

  RY                    RRYY        RRYy      RrYY        RrYy

  Ry                    RRYy         RRyy       RrYy        Rryy

  rY                     RrYY         RrYy        rrYY         rrYy

  ry                      RrYy         Rryy         rrYy         rryy

           in F2 generation genotypic ratio is: 1:2:1:2:4:2:1:2:1

                                         phenotypic ratio is 9:3:3:1

To predict the genotypic ratios, recall that for each gene the ratio is 1 : 2 : 1 :: AA : Aa : aa . Then, algebraically

(1YY + 2Yy + 1yy) x (1RR + 2Rr + 1rr) = 1 YYRR + 2 YYRr + 1 YYrr + 2YyRR + 4YyRr + 2 yyRR + 1yyRR + 2yyRr + 1yyrr

That is, we expect a characteristic 1:2:1:2:4:2:1:2:1 ratio of the nine possible genotypes.