Math, asked by lopesstanny1, 1 month ago

13. A person borrowed 8,000 to buy a
machine. If the rate of compound interest is
10p.c.p.a. what amount will he pay at the
end of 2 years?
O 31,680
O 89,680
O 59,860
O 31,860​

Answers

Answered by problems1359
0

Answer:

this is the question

A man borrowed Rs.80000 at the rate of 10% p.a. compound interest, interest being compounded annually. How much amount should he have repaid at the end of the first year, if by repaying Rs.55000 at the end of the second year he can clear the loan?

Option 1) 

Rs.38000

Option 2) 

Rs.33000

Option 3) 

Rs.45000

Option 4) 

Rs.50000

Option 5) 

Rs.40000

Step-by-step explanation:

this is the answer

P= 80000

R = 10 % ‘

after first year amount = 88000

10 % rate compounded annually

If we paid 55000 at the end of  the 2nd year it means we paid 110 % of amount left after paid certain from the 1st year . C.I always calculated on previous year amount

So that certain amount is paid after first year then the remaining amount is equal to 50000.

i.e the certain amount paid after 1st year is equal to the 

 

Answered by Anonymous
1

Answers

P= 80000

R = 10 % ‘

after first year amount = 88000

10 % rate compounded annually

If we paid 55000 at the end of the 2nd year it means we paid 110 % of amount left after paid certain from the 1st year . C.I always calculated on previous year amount

= \frac{55000}{110} \times 100 = 50000

So that certain amount is paid after first year then the remaining amount is equal to 50000.

i.e the certain amount paid after 1st year is equal to the = 88000 -50000= 38000

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