Question

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13. A water pipe (as shown in the diagram has the
inner diameter of 15/4 cm and a wall thickness of
5/7 cm. What is the outer radius of
the pipe ?
[Hint. Radius = 1/2 x diameter]​

Answer 1

Answer:

2.855cm

Step-by-step explanation:

Outer Diameter = inner diameter + 2 thickness

d1= inner diameter

d2=outer Diameter

t = thickness of pipe

Given d1= 15/4=3.75 cm

t =5/7= 0.71 cm

Now , d2= 3.75+ 2*0.71 = 5.71 cm

According to question ,

Outer radius = d2/2

= 2.855cm.

Answer 2

Answer:

answer is

Step-by-step explanation:

2 33 upon 56 cm