Question

13 ABC AC=BC,AC=42 cm and angleB - 90°. On AC as diameter a semicircle is described. Find the
area of the figure​

Answer 1

Step-by-step explanation:

area of the figure

area of ∆le +area of semi circle

• area of semi circle

πr²/2=22/7*42*42/2

=11*6**42

2772 cm²

• area of the triangle

in the figure is isosceles triangle

therefore 2 angles are equal

one angle is 90

then other two angles 45 each

We apply sin theta

sin 45=1/√2

1/√2=1/42

then 21√2

29.694cm²

it is nearly 30

area of triangle=1/2b*h

base=30, height=30

1/2*30*30

15*30=450cm²

area of figure=2772+450

3222cm²