13.
ABCD is a cyclic quadrilateral in which if angleA: angleC=2:3, then find
angleA and angleC
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draw a cyclic quad. abcd,
since, a+c =180° , therefore 2n+3n =180°
now, n=36°, so, 2(n) +3(n) =180° and a will be 72° and c =108°.
hope it helps...
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