Question

13. Abullet of mass 10g travelling horizontally with a velocity of 150 ms strikesa stationary wooden block and comes
to rest in 0.03 s. Calculate the distance of penetration of the bullet into the block. Also, calculate the magnitude of
the force exerted by the wooden block on the bullet.



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Answer 1

3m

Step-by-step explanation:

Mass=10g.=10/1000=0.01Kg.

Velocity=150m/s.

Time taken by the bullet to come to rest=0.03s.

Retardation=(u-v)/t.

=(150-0)/0.03

=150/3/100.

=15000/3.

=5000m/s.

Force =mass×acceleration.

=0.01×5000 Kg×m/s.

=50Kgm/s.

=50N.

Distance penetrated =ut-1/2at²

=150×0.03-1/2×5000×0.03×0.03.

=4.5-1/2×5000×3/100×3/100.

=4.5-3/2

=4.5-1.5=3m

Sorry to say that at the first time I gave 6m,it should be 3m,sorry for the inconvinience