Question

13. Abullet of mass 10g travelling horizontally with a velocity of 150 ms strikesa stationary wooden block and comes to rest in 0.03 s. Calculate the distance of penetration of the bullet into the block. Also, calculate the magnitude of the force exerted by the wooden block on the bullet.


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Answer 1

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To Help.....

Answer:

GIVEN :-

⇒ Mass of the bullet = 10 g

⇒Velocity of the bullet = 150 m / s

⇒ Tie taken by the bullet to take rest when it strikes the wooden block = 0.03 s

TO FIND ;-

⇒ Distance of the penetration of the bullet = ?

SOL :-

⇒ Distance is also reffered to Displacement.

⇒Displacement is the shortest distance travelled by an object.

Therefore ,

          ⇒Displacement                              = Velocity × Time 

                      

                       where average velocity is = (u + v) / 2

⇒ So displacement    =  [(u + v) / 2] × time

                                

                                 = [(150 + 0) / 2] × 0.03

         

                                 = 2.25 m

Distance of the penetration of the bullet is 2.25 m