Question

13. An object 2 cm high and at right angles to the principal axis of a concave
mirror is 15 cm from the pole. If the radius of curvature of the mirror is
20 cm, find the distance of the image from the role and its height. Is it
real or virtual?​

Answer 1

Explanation:

The radius of curvature is twice the focal length. So f = 10 cm

Object distance is given as 15 cm. Use the mirror equation 1/u + 1/v = 1/f

1/15 + 1/v = 1/10

So v = 30 cm

magnification = image size / object size = image distance / object distance.

In this case magnification is v/u = 30 / 15 =2

so image size = 2 x 2 = 4cm

Since the object distance is greater than focal length, it would be a real image (as the sign suggests in above solution). Note that v would have been negative if the object distance u was less than focal length.

Answer 2

Explanation:

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