Question

13. An object of height 2 cm is placed at 10 cm distance infront of aconcave mirror whose focal length is 15 cm. Calculate height of image.​

Answer 1

Explanation:

Focal length f=

2

R

Radius of curvature R=30

Object distance u=10cm

Height of object h

o

=2cm

From the mirror formula,

f

1

=

v

1

+

u

1

−

v

1

=

u

1

−

f

1

−

v

1

=

10

1

−

30

2

−

v

1

=

30

3−2

v=−30cm

Now, the magnification is

m=

u

−v

m=

10

30

m=3

Now, the height of image

m=

h

o

h

i

3=

2

h

i

h

i

=6cm

Hence, the image distance is −30 cm, height of image is 6 cm and magnification is 3

Answer 2

Answer:

gdugdufd uh shfxugctd

Explanation:

hi= 6cm