Question

13. An object of size 5cm is placed at a distance of 15cm infront of a
concave lens of power 10 D. The size of image is
a. -5cm b. -6cm
d. +5cm
c. 6cm
​

Answer 1

Explanation:

Answer:

Concave lens

ho=+4 cm

u=-15 cm

P=1/f f=Focal Length

-10 =1/f

f=(1/-10)×100 cm

f=-10cm

using lens formula

1/f=1/v-1/u

⇒1/v=1/f+1/u

⇒1/v= -1/10 -1/15

⇒1/v=(-3-2)/30

⇒1/v=-5/30

⇒1/v=-1/6

Image distance (v)= -6 cm

hi/ho=v/u

⇒hi=v/u×ho

⇒hi=-6/-15 ×5

⇒hi=2/5 ×5

⇒hi=10/5cm

⇒hi=2 cm

Image Height =2 cm Answer.

Answer 2

Answer:

i think d.+5cm is correct one.

Dear,i hope this will be helpful for you