Question

13. An object travels 24 m with a speed of
4 m/s and then another 32 m with
speed of 8 m/s. The average speed of
the object is
(a) 6 m/s
(b) 4 m/s
(c)5.6 m/s
(d) 6.5 m/s
14. A narticle moving in
till​

Answer 1

Explanation:

D-Distance, S-Speed, T-Time.

D1 = 24m

S1 = 4m/s

:. T1 = D1/S1 = 24/4 = 6s

D2 = 32m

S2 = 8m/s

:. T2 = D2/S2 = 32/8 = 4s

Avg. S = Total D / Total T

= (24+32)/(6+4)

= 56/10

= 5.6 m/s

Hope it helps :) Please mark me brainliest :D

Answer 2

Given:

An object travels 24 m with a speed of 4 m/s and then another 32 m with speed of 8 m/s.

To find:

Average speed ?

Calculation:

• Average speed is defined as the ratio of total distance to the total time of the object.

$\therefore \: avg. \: v = \dfrac{total \: distance}{time}$

$\implies \: avg. \: v = \dfrac{24 + 32}{ \dfrac{24}{4} + \dfrac{32}{8} }$

$\implies \: avg. \: v = \dfrac{24 + 32}{ 6 + 4 }$

$\implies \: avg. \: v = \dfrac{56}{10 }$

$\implies \: avg. \: v = 5.6 \: m {s}^{ - 1}$

So, average speed is 5.6 m/s (OPTION c)