Question

13 and 31 is a strange pair of numbers such that their squares are 116 and 961 are also mirror images of each other how find two more such pairs

Answer 1

The square of 13 and 31 are 169 and 961.

The number which tenth digit A and unit digit B is $10A+B$. The other number is $10B+A$.

The square of the first number is $(10A+B)^2=100A^2+20AB+B^2$. Each digit is A², 2AB, B², and it has to be less than 10.

→ A=1, 2, 3

→ B=1, 2, 3

23 and 32 can't be an answer since their 2AB is 12.

The numbers are 12, 13, 21, 31.

Verification 1: 12²=144, 21²=441

Verification 2: 13²=169, 31²=961

Answer 2

sorry for answering :) give the other guy brainliest thanks