13.Area enclosed between the lines x+2y-4 =0 and x+2y-2 =0 and the coordinate axes is
Answers
Given : the lines x+2y-4 =0 and x+2y-2 =0
To Find : Area enclosed between the lines x+2y-4 =0 and x+2y-2 =0 and the coordinate axes
Solution:
x+2y-4 =0 and x+2y-2 =0 are parallel lines
x+2y-4 =0
intersection with x & y axis
(0 , 2) and ( 4 , 0)
x+2y-2 =0
intersection with x & y axis
(0 , 1) and ( 2 , 0)
Area between lines x+2y-4 =0 and x+2y-2 =0 and the coordinate axes is
= Area of Triangle by (0 , 0) , ( 4 , 0) , ( 0 , 2) - Area of Triangle by (0 , 0) , ( 2 , 0) , ( 0 , 1)
Area of Triangle by (0 , 0) , ( 4 , 0) , ( 0 , 2) = (1/2) (4 * 2) = 4
Area of Triangle by (0 , 0) , ( 2 , 0) , ( 0 , 1) = (1/2) (2 * 1) = 1
Area between lines x+2y-4 =0 and x+2y-2 =0 and the coordinate axes is
= 4 - 1
= 3 Sq units
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