Question

13(b)
(iv) m 2 EBF if O A=O B, and CD= EF.
EX
(45-6x) XD
B 9x
A
Fig. 13.57​

Answer 1

Answer:

Given:- OA=OBOD=OC

To prove:- (i)△AOD≅△BOC(ii)AD∥BC

Proof:-

Line AB and CD intersect.

∠AOD=∠BOC(Vertically opposite angle)

In △AOD and △BOC,

OA=OB(Given)

∠AOD=∠BOC

OD=OC(Given)

△AOD≅△BOC(SAS congruent rule)

∠OAD=∠OBC

But ∠OAD and ∠OBC and these form a pair of alternate angles if a transversal intersects two lines such that pair of alternate interior angles is equal, then lines are parallel.

∴AD∥BC

Step-by-step explanation:

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