13. By remainder theorem, find the remainder when p(y) is divided by g(y)
i) p(y) = y 3 – 4y2 -2y + 6 and g(y) = 1 -
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Answer:
Given, p(x) = x² + x² + x² - 5x + 1 and
g(x) = x + 1
q(x) x+1=0⇒x= -1
The remainder when p(x) is divided by g(x)
isp(-1) ...(By Remainder Theorem)
Thus,
p(−1) = (−1)ª + (−1)³ + (−1)² −
5(-1) +1
p(−1) = 1−1+1+5+1
P(-1) = 7
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