Question

13. Calculate the energy and radius associated
with the second orbit of 07 +
1on​

Answer 1

Answer:

Answer

◆ Answer - E = -30.6 eV. R = 0.7053 A°

◆ Explanation - Energy associated with 2nd Bohr's orbit is - E = -13.6 Z²/n² E = -13.6 × 3² / 2²

E = -30.6 eV. Radius of 2nd Bohr's orbit in Li2+ is given by - R = 0.529 n²/Z. R = 0.529 × 2² / 3.

R = 0.7053 A°

Explanation:

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