Physics, asked by harnamsinghkhare85, 1 year ago

13. Calculate the wavelength of an electron that has been accelerated in a particle
accelrator through a potential difference of 1keV. [1eV = 1.6x10^-19 j]

Answers

Answered by raji8115

0

energy in eV = 12400/(wavelength in A°)

wavelength in A°= 12400/10³ =12.4A°

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