Question

13 chapter ke formula class 10th​

Answer 1

Answer:

CUBE

lsa=4a^2

tsa=6a^2

v=a^3

CUBOID

lsa=2(l+b)h

tsa=2(lb+bh+hl)

v=l×b×h

CYLINDER

CSA=2πrh

tsa=2πr(r+h)

v=πr^2h

CONE

CSA=πrl

tsa=πr(r+l)

v=1/3 πr^2h

Hemisphere

CSA=2πr^2

tsa=3πr^2

v=2/3 πr^2

Sphere

CSA/tsa=4πr^2

v=4/3πr^3

Answer 2

Circle

Area = $\pi r²$

Circumference = $2 \pi r$

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Cuboid

CSA = $2(l +b)(h)$

TSA = $2(lb+bh+lh)$

Volume = $length \times breadth \times height$

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Cube

CSA = $4a²$

TSA = $6a²$

Volume = $a³$

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Cylinder

CSA = $2 \pi rh$

TSA = $2 \pi r(h+r)$

Volume = $\pi r² h$

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Cone

CSA = $\pi rl$

TSA = $\pi r (l+r)$

Volume = $\frac{1}{3} \pi r² h$

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Sphere

TSA & CSA ( same for both ) = $4 \pi r²$

Volume = $\frac {4}{3} \pi r²$

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Hemisphere

CSA = $2 \pi r²$

TSA = $3 \pi r²$

Volume = $\frac{2}{3} \pi r³$

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Frustum of a cone is deleted for this year but still ...

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Frustum of a cone

CSA = $\pi (R+r)l$

TSA = $\pi (R+r)l + \pi R² + \pi r²$

Volume = $\frac {1}{3} \pi h (R²+r²+R.r)$

slant height = $\sqrt{h²+(R-r)²}$