13. Consider the reaction N2(g) +3H2 2NH3g). Explain the effect of pressure on this
equilibrium reaction.
Answers
Answered by
0
Explanation:
t=0
t=eq
2NH
3
P
1
P
NH
3
⇌
N
2
0
2
P
1
+
3H
2
0
2
3P
1
P=P
total
=
2
P
1
+
2
3P
1
=2P
1
∴P
1
=
2
P
k
eq
=
(P
NH
3
)
2
(P
N
2
)(P
H
2
)
⇒
k
p
1
=
(P
NH
3
)
2
(
2
P
1
)(
2
3P
1
)
3
∴
K
P
(P
NH
3
)
2
=
4
4
P
4
×3
3
∴P
NH
3
2
=K
p
4
4
P
4
×3
3
P
NH
3
=(K
p
4
4
P
4
3
3
)
2
1
=
16
(K
p
)
2
1
3
2
3
P
2
Answered by
0
Answer:
Explanation:
N2(g) + 3H2(g) ⇌ 2NH3(g)
In the above equilibrium, if the pressure is increased, the volume will decreases. The system responds to this effect by reducing the number of gas molecules.
i.e., it favours the formation of ammonia. If the pressure is reduced, the volume will increases. It favours the decomposition of ammonia.
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