Question

13 cos theta = 5 find the value of tan² theta- sec20 square theta​

Answer 1

Step-by-step explanation:

Given,

sinA=

13

12

We know that,

sinA=

Hypotenuse

oppositeSide

From Pythagoras theorem,

(Hypotenuse)

2

=(oppositeSide)

2

+(adjacentSide)

2

13

2

=12

2

+(adjacentSide)

2

(adjacentSide)

2

=169−144=25

(adjacentSide)=5

cosA=

Hypotenuse

AdjacentSide

=

13

5

tanA=

AdjacentSide

OppositeSide

=

5

12

Therefore,

2sinθcosθ

sin

2

θ−cos

2

θ

×

tan

2

θ

1

=

2(

13

12

)(

13

5

)

(

13

12

)

2

−(

13

5

)

2

×

(

5

12

)

2

1

=

2(

13

12

)(

13

5

)

(

169

144

)−(

169

25

)

×

144

25

=

(

169

120

)

(

169

144−25

)

×

144

25

=

120

119

×

144

25

=

24

119

×

144

5

=

3456

595

How satisfied are you with the answers