Question

13. D and E are points on the sides CA and CB<br />respectively of a triangle ABC right angled at C.<br />Prove that AB + BD=AB2+DE?. .... plz solve ..​ And fast Ans.....​ Class 10..<br /> plz help me​

Answer 1

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D and E are points on the side CA and CB respectively of triangle ABC right angled at C prove that AE²+BD²=AB²+DE²

Ask for details Follow Report by Dhanushkumar 25.02.2018

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Khushib707

Khushib707 Ace

I think you mean AE2 + BD2 = AB2 + DE2

In triangle ACE,

AC2 + CE2 = AE2 ...(i) (By Pythagoras Theorem)

In triangle DBC,

DC2 + BC2 = BD2 ...(ii) (By Pythagoras Theorem)

In triangle ABC,

AC2 + BC2 = AB2 ...(iii) (By Pythagoras Theorem)

In triangle DEC,

DC2 + CE2 = DE2 ...(iv) (By Pythagoras Theorem)

Adding (i) and (ii) we get,

AE2 + BD2 = AC2 + CE2+ DC2+ BC2

AE2 +BD2 = AC2 +BC2 +CE2 + DC2

AE2 + BD2 = AB2 + DE2 [ from (iii) and (iv)]

Hence proved

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Answer 2

ur answer is attached, hope it's help u....