Computer Science, asked by jeevankoiri, 3 months ago

13. Design the 32:1 multiplexer using 4:1 multiplexer tree concept
and implement the function F = {0, 1, 3, 8, 9, 13) using suitable
multiplexer.


For 32:1 multiplexer,
no. of inputs = 32(L, I, I.......... 131)
no. of outputs = 1
no. of selection lines = 5(S., S3, S2, S., S) -
For 4:1 multiplexer,
no. of inputs = 4(1, 11, 12, 13)​

Answers

Answered by dryash1009
1

Answer:

Explanation:

The chemicals that undergo chemical change in a

chemical reaction are called reactants.

Answered by sweetie2604
2

Answer:

we assume that we have one-bit inputs

(in general, each input may have more than one bit)

• Suppose we have eight inputs: I0, I1, I2, I3, I4, I5, I6, I7

• We want one of them to be output based on selection signals

• 3 bits of selection signals to decide which input goes to output

• Note the order of selection signals

– X is MSB and Z is LSB

Multiplexing and Multiplexer

X Y Z F

0 0 0 I0

0 0 1 I1

0 1 0 I2

0 1 1 I3

1 0 0 I4

1 0 1 I5

1 1 0 I6

1 1 1 I7

S2

S1

S0 F

0 1 2 3 4 5 6 7

I0 I1 I2 I3 I4 I5 I6 I7

X

Y

Z

8-to-1 Multiplexer

CprE 210 Lec 15 2

• We can write a logic expression for output F as follows

F = X’ Y’ Z’ I0 + X’ Y’ Z I1 + X’ Y Z’ I2 + X’ Y Z I3

+ X Y’ Z’ I4 + X Y’ Z I5 + X Y Z’ I6 + X Y Z I7

• This circuit can be implemented using

– eight 4-input AND gates and one 8-input OR gates

Multiplexer Implementation

S2

S1

S0 F

0 1 2 3 4 5 6 7

I0 I1 I2 I3 I4 I5 I6 I7

X

Y

Z

X Y Z F

0 0 0 I0

0 0 1 I1

0 1 0 I2

0 1 1 I3

1 0 0 I4

1 0 1 I5

1 1 0 I6

1 1 1 I7

CprE 210 Lec 15 3

Implementing 4-to-1 MUX using 2-to-1 MUXs

S0 2x1 MUX

0 1

I0 I1

S0 S0 2x1 MUX

0 1

I2 I3

S0

S0 2x1 MUX

0 1 S1

CprE 210 Lec 15 4

Making a 2-bit 4-to-1 Multiplexer

X

Y F

0 1 2 3

4-1 S1 MUX

S0

X

Y F

0 1 2 3

4-1 S1 MUX

S0

X

Y

ABCD

• Four 2-bit inputs A, B, C, D

• One 2-bit output F

• Two bits of selection signal X Y

F

X Y F

0 0 A

0 1 B

1 0 C

1 1 D

CprE 210 Lec 15 5

• Multiplexers can be directly used to implement a function

• Easiest way is to use function inputs as selection signals

• Input to multiplexer is a set of 1s and 0s depending on the

function to be implemented

• We use a 8-to-1 multiplexer to implement function F

• Three select signals are X, Y, and Z, and output is F

• Eight inputs to multiplexer are 1 0 1 0 1 1 0 0

• Depending on the input signals

– multiplexer will select proper output

Synthesis of Logic Functions using Multiplexers

X Y Z F

0 0 0 1

0 0 1 0

0 1 0 1

0 1 1 0

1 0 0 1

1 0 1 1

1 1 0 0

1 1 1 0

S2

S1

S0 F

X 0 1 2 3 4 5 6 7

Y

Z

10101100

CprE 210

Similar questions