Question

13. Divide the following:
6abc - 2a²c + 9b2 - 3ab by (2ac + 3b)​

Answer 1

Answer:

$\frac{6abc - 2a {}^{2}c + 9b { }^{2} - 3ab}{(2ac + 3b)} \\ \\ 6abc - 2a {}^{2} c + 9b {}^{2} - 3ab \\ \\ = 2ac(3b - a) + 3b(3b - a) \\ \\ = (3b - a)(2ac + 3b) \\ \\ \frac{6abc - 2a {}^{2} c + 9b {}^{2} - 3ab}{2ac + 3b } \\ \\ = \frac{(3b - a)(2ac + 3b)}{2ac + 3b} \\ \\ = (3b - a)$