Question

13. Divide the polynomial (6x +11x?-10x-7) by the binomial (2x + 1). Write the quotient
and the remainder.​

Answer 1

Step-by-step explanation:

Right Question-Divide the polynomial (6x³ + 11x² - 10x - 7) by the binomial (2x + 1). Write the quotient and the remainder.

6x³ + 11x² - 10x - 7

= 6x³ + 3x² + 8x²  + 4x  - 14x - 7  + 0

= 3x²(2x + 1) + 4x(2x + 1) - 7(2x + 1) + 0

= (3x² + 4x - 7)(2x+1) + 0

((6x³ + 11x² - 10x - 7)/(2x + 1)

=  ((3x² + 4x - 7)(2x+1) + 0) / (2x + 1)

Cancelling 2x + 1 from numerator & denominator

= 3x² + 4x - 7  

Quotient = 3x² + 4x - 7

Remainder = 0

Answer 2

Step-by-step explanation:

hope it's help you

answer by aman