Question

13. Equation of a wave travelling on a string isY = 0.1 sin (300t - 0.01x)Here x is in cm and t is in seconds. Find :(a) Wavelength of the wave;(b) Time taken by the wave to travel 1 m.​

Answer 1

Answer:

Required time = 1/300 second

wave length = 6•28 meter.

Explanation:

Given y= 0•1Sin( 300t -- (1/100)x)

Comparing it with the standard eqn of wave

y = A•Sin( wt-- kx) A: amplitude, w= angular velocity

k : wave number = 2( pi)/Ib

b= wave length

velocity v = w/k = 300/0•01 = 30000 cm/ sec Ans.

Time taken T to travel 1 meter = 100cm/30000 sec

= 1/300 second.

and wave length b = 2( pi)/k b( lambda sign

not key board)

b = 2/(1/100) x 3• 14

200 x 3•14 = 628 cm = 0• 6•28 m Ans