Math, asked by ramyapappu, 6 months ago


13. Evaluate (8x + 3y)2 by using a suitable identity.​

Answers

Answered by harshitasingh3260
4

Answer:

(8x+3y) ^2

the identity which we use in given eq.

= (a+b) ^2= a^2+b^2+2ab

= 64x^2+ 9y^2+2× 8x×3y

= 64x^2+ 9y^2 + 48 xy

Answered by Goldenice17
0

Answer:

64 {x}^{2}  + 48xy + 9 {y}^{2}

Step-by-step explanation:

by identity (a+b)^2 we can do this,

as

 {(a + b)}^{2}  =  {a}^{2}  +  2ab +  {b}^{2}

now just we have to put the values,

a=8x and b=3y,

therefore,

 {(8x + 3y)}^{2}  =  (8x)^{2}  + 2 \times 8x \times 3y +  {(3y)}^{2}

which equals to,

 {(8x + 3y)}^{2}  =  {64x}^{2}  + 48xy +  {9y}^{2}

Hope it helps you and please mark me as brainliest for this...

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