13. Find the area of a triangle, whose sides are 26 cm,
28 cm and 30 cm respectively. Find the height
corresponding to the longest side.
the answer is 336,22.4
Answers
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0
Answer:
the answer of triangle
Step-by-step explanation:
Given the sides of triangle 26 cm, 28 cm and 30 cm.
we have to find the area of triangle
By heron's formula
Area=\sqrt{s(s-a)(s-b)(s-c)}Area=
s(s−a)(s−b)(s−c)
where s is semiperimeter i.e
s=\frac{a+b+c}{2}s=
2
a+b+c
Sides of triangle 26 cm, 28 cm and 30 cm.
s=\frac{26+28+30}{2}=\frac{84}{2}=42 cms=
2
26+28+30
=
2
84
=42cm
Area=\sqrt{42(42-26)(42-28)(42-30)}Area=
42(42−26)(42−28)(42−30)
=\sqrt{42\times 16\times 14\times 12}=\sqrt{112896}=336 cm^2=
42×16×14×12
=
112896
=336cm
2
\text{The of triangle is }336 cm^2The of triangle is 336cm
2
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