Question

13. Find the length of tape required to cover the edges of a semicircular dis
of radius 14cm.
(C) 84cm
(D) 96cm
(A) 60cm
(B) 72cm​

Answer 1

Answer:

k

Step-by-step explanation:

k

Answer 2

$\Large{\underline{\underline{\textsf{\maltese\: {\red{Given :-}}}}}}$

☞ Radius of circular disc = 14cm

$\Large{\underline{\underline{\textsf{\maltese\: {\red{To Find :-}}}}}}$

☞ The length of tape required to cover the edges of a semicircular disc = ?

$\Large{\underline{\underline{\textsf{\maltese\: {\red{Concept Implemented :-}}}}}}$

☞ Circumference of circle (⭕) = 2πr

☞ Semi Perimeter of circle (⭕) = πr

☞ Diameter = 2 × Radius

$\Large{\underline{\underline{\textsf{\maltese\: {\red{Solution :-}}}}}}$

» Length of tape required = Semi Perimeter of circular disc + Diameter

» Length of tape required

= πr + d

= πr + 2r

= r(π + 2)

= ${14(\dfrac{22}{7} + 2 )}$cm

= ${14(\dfrac{22 \; + \; 14}{7})}$cm

= $14 \; * \; \dfrac{36}{7}$ cm

= 2 × 36 cm

= 72cm

∴ The length of tape required to cover the edges of a semicircular disc is $\underline{\underline{\bf{72 \:cm}}}$.