13. Find the lowest natural number which when divided by 15, 20, 25 and 45 leaves a remainder 8 in each case
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Answered by
4
Answer: 908
Step-by-step explanation:find the LCM of 20, 25, 35 and 40. The deduct 6 from 1400 to get 1394, which is the required number. According to the question, the remainder should be 8, So we'll add 8 to 900 that is answer is 908.
Answered by
1
Answer:
Here is your answer bro
Step-by-step explanation:
Let us see the relation between the pairs of numbers if there is any:
20 - 14 = 6
25 -19 = 6
35 - 29 = 6
40 - 34 = 6.
The difference is 6, so there is a pattern
Next find the LCM of 20, 25, 35 and 40.
20 = 2x2x5
25 = 5x5
35 = 5x7
40 =2x2x2x5
So LCM = 2^3x5^2x7 =1400
The deduct 6 from 1400 to get 1394, which is the required number.
Check: 1394/20 = 69Q + 6R
1394/25 = 55Q + 19R
1394/35 = 39Q + 29R
1394/40 = 23Q + 34R
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