Question

13. FIND THE ROOTS OF THE QE. X² + 7X + 5 = 0.

Answer 1

Answer:

√2 x² +7x +5 √2 = 0

⇒ √2 x² + 5x + 2x + 5√2 = 0

⇒ √2x² + 5x + √2*√2*x + 5√2=0

⇒ x(√2x + 5) + √2(√2x + 5) =0

⇒ (x+√2)(√2x+5) = 0

That gives x= - √2 or x= - 5/√2