Question

13. Find the solution of the following pair of linear
equations:

x - y = 3 and 4x + 2y = 0​

Answer 1

Answer:

x−y=3

4x+2y=0

or 2x+y=0

Eqn(2)+(1)

⇒2x+y+x−y=0+3=3

3x=3

∴x=

3

3

=1

substitute x=1 in (2) we get

2x+y=0⇒2×1+y=0

⇒y=−2

∴x=1,y=−2

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Answer 2

Answer:

4X - X = 3X and 2Y + Y=3Y

therefore 3x and 3Y=3X+3Y =6XY