13. Find the sum of the first 15 multiples of 8.
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Step-by-step explanation:
The first 8 multiples of 8 are
8,16,24,32,40,48.56,64...
These are in an A.P.having first term as 8 and common difference as 8
Therefore a=8
d=8
S15=?
Sn=n/2 (2a+ (n-1)d)
S15=15/2 (2(8)+ (15-1)8)
15/2(6+(14)(8))
15 (128)/2
15×64=960......
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