Question

13) Find the tenth term from the end of the A.P. 6, 13, 20, ----------,216.​

Answer 1

Step-by-step explanation:

a=13

d=7

an=216

a10=?

an=a+(n-1)d

=13+(10-1)7

=13+63

a10=76

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Answer 2

Answer:

The tenth term from the end of the A.P. 6, 13, 20, ----------,216. is 153

Step-by-step explanation:

• Arithematic progression is defined as a series in which the difference between the succesive terms gives a common number called common difference.
• The nth term of AP is defined as

     $a_n=a+(n-1)d$

      where a is the first term, n is the number of the terms and d is the

       common difference.

Step 1 of 1:

• first term of AP is 216
• Common difference =13-20=-7
• The tenth term of AP is given by

       $a_n=a+(n-1)d$

     $a_{10}=216+(10-1)(-7)\\a_{10}=216+9\times(-7)\\a_{10}=216-63\\a_{10}=153$