Math, asked by hemanthsy3032, 8 months ago

13.Find the value of ( 6^0 × 5^0 )+ (8^0 * ÷ 3^0)

Answers

Answered by Darkrai14
1

\rm \bigg ( 6^0 \times 5^0 \bigg ) + \bigg ( 8^0 \div 3^0 \bigg  )

Any number except 0 raised to the power 0 is 1.

In other words, a⁰ = 1 if a ≠ 0

So here, all the numbers will become 1 since, they all have their power as 0.

\rm\dashrightarrow \bigg ( 1 \times 1 \bigg ) + \bigg ( 1 \div 1 \bigg )

\rm\dashrightarrow 1+ 1

\bf\dashrightarrow 2

Hence, the answer is 2.

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