Question

(13) Find two consecutive numbers such
that the difference of their squares
is 45.​

Answer 1

let the two numbers be x and x+1

according to the question:

(x+1)^2 - x^2 = 45

x^2+1+2x - x^2 = 45

2x + 1 = 45

2x= 44

x = 22

the other number is x+1 = 22+1 = 23

therefore, the two consecutive numbers are 22 and 23

Hope it helped u....

Answer 2

Let the numbers be 'x' and 'x+1'. Then,

(x+1)^2 - x^2 = 45

x^2 + 2x + 1 - x^2 = 45

2x + 1 = 45

2x = 45 - 1

x = 44/2

x = 22.

Hence, the numbers are 22 and 23. (x + 1 = 22 + 1 = 23)

Hope it helps you.

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