Math, asked by Daxish, 7 months ago

13.Findtherootsofthequadraticequation:2x²-7x+3=0​

Answers

Answered by pragatimaniyar13
2

Step-by-step explanation:

2x²-7x+3=0

2x^2-6x-x+3=0

2x(x-3)-1(x-3)=0

(2x-1) (x-3) =0

2x-1=0 x-3=0

2x=1 x=3

x=1/2

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