Question

13. Five years ago a man was seven times as old as his son. Five years hence, the father will be three times as old as his son. Find their present ages.​

Answer 1

Answer:

Age of the son =x

Age of the father=7x

Present ages=x+5 and 7x+5

future age of the son=x+10

father=7x+10

7x+10=3(x+10)

x=5

7x=35

x+5=5+5=10

son age =10

father age =7x+5=7*5+5=40