13.For what value of (k) x = 2, y = 1, is a solution of x +3y-k = 0
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Given equation x + 3y - k = 0. Substitute x = 2 and y = -1 then we get ⇒ 2 - 3 - k = 0 k = -1. when k = -1, x = 2 and y = -1 is a solution of x + 3y - k = 0.
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Answer:
x+3y-k=0
2+3×1 = k+0
5=k+0
k=5
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