Question

13- For what values of K, the q + 6x +10 has real roots.
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Answer 1

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Appropriate Question :-

For what values of K, the kx² + 6x + 10 has real roots.

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To Find :-

Value of k

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By The Form of :-

ax² + bx + c = 0

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So Here..,

a = k , b = 6 , c = 10

ᐃ = b² - 4ac

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Since The Rules Are Equal..,

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Discriminant = b² - 4ac = 0.

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∴ b² - 4ac = 0

∴ 6² - 4 × k × 10 = 0

∴ 36 - 40k = 0

∴ - 40k - 36 = 0

∴ k = ( - 40 ) ÷ ( - 36 )

∴ k = 10/9

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