Math, asked by shrivastavadeepsikha, 3 days ago

13 .Four bells ring at intervals of 3, 7, 12, and 14 minutes, respectively. All four rang together at 12 noon. When will they ring together again? nf rihhon One niece is 720 cm long and the other piece is 900 cm 1​

Answers

Answered by purushothamvajjula
0

Answer:

Step-by-step explanation:The four bells ring together again at 9 pm

Solution:

Given that,

Four bells rings at intervals of 8 , 10 , 12 , 14 minutes respectively

Find LCM of 8, 10, 12 and 14

List all prime factors for each number.

Prime Factorization of 8 is: 2 x 2 x 2

Prime Factorization of 10 is: 2 x 5

Prime Factorization of 12 is: 2 x 2 x 3

Prime Factorization of 14 is: 2 x 7

For each prime factor, find where it occurs most often as a factor and write it that many times in a new list.

2, 2, 2, 3, 5, 7

Multiply these factors together to find the LCM.

LCM = 2 x 2 x 2 x 3 x 5 x 7 = 840

Thus the four rings will together at 840 minutes

1 hour = 60 minutes

Thus,

840 minutes = 14 hours

They rang at 7 a.m

They will ring together again at = 7 am + 14 hours = 9 pm.

Thus they ring together again at 9 pm.

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Answered by muskanjangde861
1

Step-by-step explanation:

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