Math, asked by kumarsharatkumar, 3 months ago

13. From the top of a cliff 92 m high, the
angle
of
of depression of a buoy is 20°. Calculate,
to the nearest metre, the distance of the buoy
from the foot of the cliff.​

Answers

Answered by rahul291997
1

Answer:

253 m

Step-by-step explanation:

Let AB be the cliff and C be the buoy.

AB=92m(Given)

Also,

∠ACB=20°

Therefore,

In △ABC,

tan20°=

Bc

AB

⇒BC=

0.364

92

≈253m

Hence the buoy is at a distance of 253m from the foot of the cliff.

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