Question

13. If 1 and 2 are two zeros of the polynomial (x³-4x²-7x+10), find its
third zero.​

Answer 1

Step-by-step explanation:

To find the third zero we need to divide the polynomial with any of its factors:

(x^3-4x^2-7x+10)÷(x-1)

=x^2-3x-10

now we need to factorise it

Sum=-3

Product=-10

Numbers=-5,2

x^2-5x+2x-10

(x^2-5x)+(2x-10)

x(x-5)2(x-5)

(x+2)(x-5)

ANS:the third zero can be either -2or +5.