Question

13. If 15 cot 0 = 8, then find the value of (1 - sin 0)(1+ sin 0)
(1 + cos 0) (1 - cos 0)​

Answer 1

Step-by-step explanation:

15cot 0 = 8

cot 0= 8/15

cot 0= B/P

Let B=8 x

P= 15x

by Pythagoras theorm,

H²=B²+P²

H²= (8x)² + (15x)²

H²= 64x² + 225x²

H²= 289x²

H= 17x

Now,

(1-sin0) (1+sin0)

= 1²-sin²0

= 1-sin²0

= cos²0

= (8/17)²=64/289

(1-cos0) (1+cos0)

= 1-cos²0

= sin²0

= (15/17)²

= 225/289